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please show your work. F(x)=2-3x^2 and g(x)=x+2. find f 0 g and g 0 f
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fog = 2-3(x+2)^2
gof = (2-3x^2) +2
you can simplify urself
how do I do it?
caqn you walk me through the steps
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fog = 2 -3(x+2)(x+2) etc gof = 2 -3x^2 +2 = -3x^2
if fo g the g function takes the place of the x as it is f(g(x)) in the gof function we place the f function for the x in g
ok
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