Solve this problem.
\[15r^2+31rs+10s^2=15r^2+25rs+6rs+10s^2\]
Factor by grouping.
Look what the 1st and 2nd terms have in common and factor it out. Do the same for the 3rd and 4rt terms.
hmmm ok ill try
1st and 2nd divisible by 5 and they have variable in common.
Sorry im no good at this kinda stuff.
5r(3r+5s) + 6rs + 10s^2 try to do the same for the 3rd and 4th
the 3rd and 4th variables or 3rd and 4th solutions
3rd and 4th terms: 6rs + 10s^2. Both are even and they have variable in common. Please try.
I am the reason i posted this one is cause i got it wrong and messed up somewhere and the term is 30 isnt it?
what variable 6rs and 10s^2 have in common?
oh variable sorry s
Good, now 6 and 10 have something in common?
hmmm either 30 or 60
Lets look this way: 6=2*3, 10=2*5. What they have in common?
oh the 2 is in both sides
YES! now, 6rs + 10s^2=2s(3r+5s)
5r(3r+5s) + 2s(3r+5s) One more time: something in common?
hmm s and r and ummm idk the 2nd part
try again. You almost done.
It's easier and faster just give an answer, but I want you to learn something.
And yes i know i need to learn thanks this stuff is hard for me
O well. (3r+5s)(5r + 2s) You can check answer by doing FOIL
ok thanks
you are welcome
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