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Mathematics 9 Online
OpenStudy (anonymous):

Solve this problem.

OpenStudy (anonymous):

\[15r^2+31rs+10s^2=15r^2+25rs+6rs+10s^2\]

OpenStudy (anonymous):

Factor by grouping.

OpenStudy (anonymous):

Look what the 1st and 2nd terms have in common and factor it out. Do the same for the 3rd and 4rt terms.

OpenStudy (anonymous):

hmmm ok ill try

OpenStudy (anonymous):

1st and 2nd divisible by 5 and they have variable in common.

OpenStudy (anonymous):

Sorry im no good at this kinda stuff.

OpenStudy (anonymous):

5r(3r+5s) + 6rs + 10s^2 try to do the same for the 3rd and 4th

OpenStudy (anonymous):

the 3rd and 4th variables or 3rd and 4th solutions

OpenStudy (anonymous):

3rd and 4th terms: 6rs + 10s^2. Both are even and they have variable in common. Please try.

OpenStudy (anonymous):

I am the reason i posted this one is cause i got it wrong and messed up somewhere and the term is 30 isnt it?

OpenStudy (anonymous):

what variable 6rs and 10s^2 have in common?

OpenStudy (anonymous):

oh variable sorry s

OpenStudy (anonymous):

Good, now 6 and 10 have something in common?

OpenStudy (anonymous):

hmmm either 30 or 60

OpenStudy (anonymous):

Lets look this way: 6=2*3, 10=2*5. What they have in common?

OpenStudy (anonymous):

oh the 2 is in both sides

OpenStudy (anonymous):

YES! now, 6rs + 10s^2=2s(3r+5s)

OpenStudy (anonymous):

5r(3r+5s) + 2s(3r+5s) One more time: something in common?

OpenStudy (anonymous):

hmm s and r and ummm idk the 2nd part

OpenStudy (anonymous):

try again. You almost done.

OpenStudy (anonymous):

It's easier and faster just give an answer, but I want you to learn something.

OpenStudy (anonymous):

And yes i know i need to learn thanks this stuff is hard for me

OpenStudy (anonymous):

O well. (3r+5s)(5r + 2s) You can check answer by doing FOIL

OpenStudy (anonymous):

ok thanks

OpenStudy (anonymous):

you are welcome

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