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What is the value for y? 5 square root 2 5 square root 3 10 5
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and the value for x.
5=y*cos45° => y = 5/cos45 => \[5\frac{2}{\sqrt2}\] => answer is A.
x = y*sen45 => x = \[5\sqrt2 * \frac{\sqrt2}{2}\] = 5
x=5 \[5^2+5^2=y^2 =>50=y^2 =>y=\sqrt{50}= \sqrt{25} \sqrt{2}=5 \sqrt{2}\]
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this is a 45 45 90 triangle so x would have to = 5
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