Question

here's an easy one
no cheating
don't go to wolframalpaha
\int_{}^{} \frac{e^{x}}{1+e^{2x}} dx
here's an easy one
no cheating
don't go to wolframalpaha
\int_{}^{} \frac{e^{x}}{1+e^{2x}} dx
@Mathematics

Answer 1

\[\int\limits_{}^{} \frac{e^{x}}{1+e^{2x}} dx \]

Answer 2

substitution!

Answer 3

yes!

Answer 4

let e^x = u

Answer 5

then we have arctan(u)+C
=arctan(e^x)+C
gj :)

Answer 6

see easy :)

Answer 7

how? im in 7th!!!