Question

It takes one crew 6 hours to clean an auditorium after an event. If a second crew helps, it only takes 2 hours. How long would it take the second crew, working alone, to clean the auditorium?


@Algebra Help!

Answer 1

first crew has rate of
\[\frac{1}{6}\] put second crews rate as R then
\[(\frac{1}{6}+R)\times 2=1\] solve for R

Answer 2

get
\[\frac{1}{6}+R=\frac{1}{2}\]
\[R=\frac{1}{2}-\frac{1}{6}=\frac{1}{3}\] to there rate is 1/3 per hour and it would take them 3 hours working alone