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Mathematics 17 Online
OpenStudy (anonymous):

e^ln2 - evaluate the expression e^ln2 - evaluate the expression @Mathematics

OpenStudy (anonymous):

log 2

OpenStudy (anonymous):

\[e ^{\ln2}\]

OpenStudy (anonymous):

2

OpenStudy (anonymous):

ln2 is the inverse of e?

OpenStudy (anonymous):

e^ln(x)=x

OpenStudy (anonymous):

hmm i am lost

OpenStudy (anonymous):

thanks

OpenStudy (anonymous):

hah im so dumb.. i understand.. !!!

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