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Mathematics 8 Online
OpenStudy (anonymous):

since p|[p1p2...p(n-1)] and p|P, where P=p1p2...p(n-1) and p is a prime number, .... FILL IN THE BLANK PLEASE since p|[p1p2...p(n-1)] and p|P, where P=p1p2...p(n-1) and p is a prime number, .... FILL IN THE BLANK PLEASE @Mathematics

OpenStudy (anonymous):

oops sorry, P=p1p2...p(n-1) +1

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