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The equation for a parabola that opens upward and has a vertex in the second quadrant is given by y = a (x - b)2 + c. Choose all of the conditions below that would apply to this equation. a<0 a>0 b<0 b>0 c<0 c>0
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a>0, b>0, c<0
oop s that the 4th quad so you need a > 0, b<0 and c> 0 for the 2nd
for example y = 2(x+3)^2 +5 has vertex at (-3, 5) in quad 2
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