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For f(x)=sqrt x-1 and g(x)=1/x-2 find the domain of fg
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\[x>1,x \neq2, x \epsilon R\]
assuming (x-1) and 1/(x-2)
what does the xeR mean?
x is an element of Real numbers ... the epsilon means "is an element of"
are u ok with this answer?
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fg =\[\sqrt{x-1}/(x-2)\] so x -1> 0 but x \[\neq 2\]
srry x can equal 1 so w\[x \ge 1, x \neq 2\]e have
made a slip there
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