Question

2/3x-1 + 3/3x+1 = 4

Answer 1

first you need calcule the denominatoe common
how many will be ?

Answer 2

so if 3x-1 and 3x+1 are there like denominators of those fractions the denominator common how many will be ?

Answer 3

multiply 3x-1 by 3x+1 and will get 9x2 -1 like denominator common

Answer 4

so than the first numerator you need multiply by 3x+1 and second numerator by 3x-1 than will get

(2(3x+1)+3(3x-1))/(9x2 -1) =4(9x2 -1)/9x2 -1
6x+2+9x-3=36x2 -4
15x-1=36x2 -4
36x2 -15x -3 =0 divide both sides by 3
12x2 -5x -1=0

Answer 5

so can you solve this quadratic equation ?

Answer 6

so x1,2=(5+/- sqrt(25+48))/24 =(5+/- sqrt73)/24