Question

x2+12x−64=0 need help with this problem, so please help

Answer 1

is it \[x^{2}\] or 2x

Answer 2

4 , -16

Answer 3

if it is x^2

Answer 4

if it is \[x^{2}\] then here is a solution:
\[x ^{2}+16x-4x-64 = 0\]
\[x(x+16)-4(x+16)=0\]
(x+16) (x-4) = 0
x = 4 or x= -16