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How can I integrate this?\[\int_{0}^{2}\int_{0}^{1}(2x+y)^8dxdy\]
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Just integrate it calmly as you might expect. The inner integral, that wrt x, is just \[ \left.\frac{1}{18} (2x + y) \right|_{x=0}^1 \] Evaluate that then integrate wrt y.
1/18 . (2x + y)^9
oh i see it now. many thanks JamesJ
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