Question

3x + 3y - 2z = 13
6x + 2y - 5z = 13
7x + 5y - 3z = 26
Solve for x,y,and z. Show your work. @Mathematics

Answer 1

multiply fisrt by -2 and assume with second
-6x-6y+4z=-26
6x+2y-5z=13
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0 -4y-z=-13

multiply second by -7and 3rd by 6
-42x-14y+35z=-91
42x+30y-18z=156
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0 16y+17z= 65 so than we have

-4y-z=-13 divide both sides by -1 and will get 4y+z=13 so than z=13-4y
16y+17z=65
- if z=13-4y than 16y+17(13-4y)=65
16y+221-68y=65
-52y=-156 divide by -1
52y=156
y=156/52 =78/26 =39/13 = 3
so y=3 than -4(3)-z=-13 so -12-z=-13 so -z= -1 so z=1
than we get from 3x+3y-2z=13 so 3x+9-2=13 so 3x=6 so x=2

than

x=2
y=3
z=1

Answer 2

Thanks
can u help me with 3 more?