Question

Find the critical numbers of 2/3*x^(-1/3).
So, [2/3*x^(-1/3)]=0 and solve for zero.
@MIT 18.01 Single …

Answer 1

I got it, it will have one critical number at 0.
2=0
=0

and
3x^(1/3)=0
x^(1/3)=0
x=0