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Mathematics 14 Online
OpenStudy (anonymous):

need help on the attachment @Calculus1

OpenStudy (anonymous):

OpenStudy (anonymous):

i want you to notice that there is a derivative of something, available right in the integral, can you tell me what it is?

OpenStudy (anonymous):

squrt(x)+2

OpenStudy (anonymous):

well, correct. What is the derivaitve of sqt(x)+2?

OpenStudy (anonymous):

1/2squrt(x)

OpenStudy (anonymous):

okay now can you tell me, if u=sqrt(x)+2, what dx will be?

OpenStudy (anonymous):

2du=sqrt(x)dx

OpenStudy (anonymous):

well wait aminute:|dw:1321498394258:dw|

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