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Mathematics 8 Online
OpenStudy (anonymous):

need help on the attachment @Calculus1

OpenStudy (anonymous):

OpenStudy (anonymous):

did you finally get that last problem

OpenStudy (anonymous):

which one?

OpenStudy (anonymous):

yeah it was the 3rd option

OpenStudy (anonymous):

the graph

OpenStudy (anonymous):

and for this one,if i'm not mistaken you should set them equal to each other

OpenStudy (anonymous):

\[x=-2,0,1\] by solving \[1+x-x^2-x^3=1-x\]

OpenStudy (anonymous):

it was the 3 one, the only one that left is 1,2, and last one 5

OpenStudy (anonymous):

\[1+x-x^2-x^3=1-x\] \[x^3+x^2-2x=0\] \[x(x^2+x-2)=0\] \[x(x+1)(x-2)=0\] etc

OpenStudy (anonymous):

I meant it was not 3 the only one that left 1,2,5

OpenStudy (anonymous):

satellite73 the x=0,-1, 2

OpenStudy (anonymous):

that should be it yes

OpenStudy (anonymous):

but there no answer choice that math except x=0,1,-2

OpenStudy (anonymous):

sat can you look at her last question? about the visual representation of the integral?

OpenStudy (anonymous):

oops! I meant match not math

OpenStudy (anonymous):

sometimes i have problems thinking straight, so sat should be able to help yu with that question

OpenStudy (anonymous):

its ok, but I the answer that satellite got is not right

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