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Find the equation of the tangent line to the graph of the given function at the point with the indicated x-coordinate. f(x) = x + 2/x; x = 2
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\[f(x)=\frac{x+2}{x}\] \[f'(x)=\frac{-2}{x^2}\] \[f'(2)=-\frac{1}{2}\] is your slope, and your point is \[(2,2)\] and point slope formula give the answer
Wait let me rewrite that equation.
f(x) = x + (2/x); x = 2
well... same idea, different answer
My answer was y=-x+5 but it was incorrect.
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f prime of x = 1 + (-2/x^2) right?
\[f'(x)=1-\frac{2}{x^2}\] \[f'(2)=1-\frac{1}{2}=\frac{1}{2}\] now use point slope with \[(2,3)\]
Oh I see. I plugged in one instead of 2.
.5x+4?
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