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OpenStudy (anonymous):
x2-16=0... add 16 to both sides, making it x2=16 Find the square root of both sides, and since 16 has an even square, the solution is x=4 and x=-4 i understand how this works, but i need "another way" to do this problem.
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OpenStudy (anonymous):
Factorise it. x^2 - 16=0 <=> (x+4)(x-4)=0
OpenStudy (anonymous):
ok.. thanks
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