solve sqrt 9x+55=x+5
flycherry u should try this by yourself, if ur stuck somewhere i'll help u
did u try flycherry??
ok
no i dint try because i dont know where to start lol
ohk we have\[\sqrt{9x+55}=x+5\] now square both sides
so I am squaring the 9 and the 5 at the end?
thats 81 and 25
no. square both sides
i dont know what that means
left hand side has a root so if u square it u are left with 9x+55
that makes absolutely no sense tome
now on the right hand side we have (x+5) you know (a+b)^2=a^2+b^2+2ab apply this to right hand side
if you are squaring a root then it would be 2sqrt then the rest... lol
nope
square root of 4 is 2 if you square 2 you get 4 again , did u understand
square of a square root term and we r left with only the term
are u getting my point
omg this same question is on my test
see our question is \[\sqrt{9x+55}=x+5\] now square right hand side as well as the left hand side we get \[9x+55=(x+5)^{2}\]
now use the formula for (a+b)^2=a^2+b^2+2ab
so we get \[9x+55=x^2+5^2+10x\]
\[9x+55=x^2+25+10x\] bring all the terms to left hand side we get 0=x^2+x-30
now factor the term 30,such that both factors differ by 1 5,6 are the two factors of 30 satisfying this
so x can be written as 6x-5x
our equation can be rewritten as x^2+6x-5x-30=0
now take out the common factors x(x+6)-5(x+6)=0 takin out (x+6) common we get (x+6)(x-5)=0 so x=-6 or x=5
flycherry did u understand?
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