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Here is my question: (will have to type so be patient with me lol :)
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\[(x-1)^{2}=8\]
use square root property to solve equation, show me how, please? :)
i would take the square root of both sides
x-1=sqrt(8) x-1=2.828 x=3.828
i know there are two answers? just not sure how to get em.
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\[x=1 \pm \sqrt8\]
x-1=+sqrt(8) or -sqrt(8) x-1=2.828 or -2.828 x=1+2.828 or 1-2.828 x=3.828 or -1.828
Thanks Sarah :) that looks right, how did you get it?
\[(x-1)^2 =8\]take the squareroot of both sides\[x-1=\pm \sqrt8\]
\[x=1 \pm \sqrt8\]
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it told me it wants the answer to look like this?---> example 3+5 and the square?
|dw:1321556074942:dw|
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