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Find the solution to the equation 64^(3 – x) = 4^2x Find the solution to the equation 64^(3 – x) = 4^2x @Mathematics
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64 = 4^3 thus \[ 64^{3-x} = 4^{3(3-x)} = 4^{9-3x} \] Now can solve this?
4^3(3-x)=4^(2x) 9-3x=2x x=1.8
Now can you solve this? Because now you know the original equation is equivalent to 4^(9-3x) = 4^(2x)
I got x = 9/5
right.
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