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The sum of the squares of two consecutive positive even integers is one hundred. Find the two integers.
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x^2+(x+2)^ 2= 100 x^2+x^2+4x+4=100 2x^2+4x-96=0 x^2+2x-48=0 (x+8)(x-6)=0 x=-8 0 or 6 The problem specifies positive so the required integers are 6 and 8
try some numbers and see if it works
satellite can u come help me
for example 4 and 6 don't work because \[4^2+6^2=16+36\] so try 6 and 8
We usually use these numbers in right triangle for hypotenuse. 3^2+4^2=5^2 6^2+8^2=10^2 5^2+12^2=13^2
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