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Mathematics 10 Online
OpenStudy (anonymous):

find the fixed points or points of the function if any g(x)=x^2-4x+1

jhonyy9 (jhonyy9):

x1,2 =(4+/- sqrt(16-4))/2 =(4+/- 2sqrt3)/2 = 2+/- sqrt3 so this x1 and x2 are the zeros points of this function

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