Question

help please,how do you solve 2^x=10 ??? help please,how do you solve 2^x=10 ??? @Mathematics

Answer 1

\[x=\frac{\log(10)}{\log(2)}\]

Answer 2

take log both sides
xlog2 =log 10
assuming base to be 10
x*0.414=1
now find x =1/0.414

Answer 3

or if you prefer
\[x=\frac{1}{\log(2)}\] or even
\[\frac{\ln(10)}{\ln(2)}\]

Answer 4

solve
\[b^x=A\] for x via
\[x=\frac{\log(A)}{\log(b)}\] this is called the "change of base" formula

Answer 5

ok htank u all :)