Question

Prove that:
\[\lim_{x \to 0}\frac{e^{-\frac{1}{x^2}}}{x^m}=0\]
For any (real) m. Prove that:
\[\lim_{x \to 0}\frac{e^{-\frac{1}{x^2}}}{x^m}=0\]
For any (real) m. @Mathematics