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6z^2+12z-az-2a... in this problem is the root -2? And if so how do i find the 2nd root?
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or is the answer just (z+2)
6z^2+12z-az-2a 6z(z+2) -a(z+2) (6z-a) (z+2)
so that would be the answer?
i believe so..
Thanks and so if you dont have a root for a you just put 6z-a?
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Yes, otherwise if u want a numeric value, substitute the value of z=-2 in 6z-a and solve further.
Ok thanks man.
uw.
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