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Mathematics 12 Online
OpenStudy (anonymous):

6z^2+12z-az-2a... in this problem is the root -2? And if so how do i find the 2nd root?

OpenStudy (anonymous):

or is the answer just (z+2)

OpenStudy (saifoo.khan):

6z^2+12z-az-2a 6z(z+2) -a(z+2) (6z-a) (z+2)

OpenStudy (anonymous):

so that would be the answer?

OpenStudy (saifoo.khan):

i believe so..

OpenStudy (anonymous):

Thanks and so if you dont have a root for a you just put 6z-a?

OpenStudy (saifoo.khan):

Yes, otherwise if u want a numeric value, substitute the value of z=-2 in 6z-a and solve further.

OpenStudy (anonymous):

Ok thanks man.

OpenStudy (saifoo.khan):

uw.

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