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Consider a triangle with a=3, b=7 and C=37 degree angle. Use the Law of Cosines to find small c (side). Round to nearest tenth.
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do you know the law of cosines ?
|dw:1321720965811:dw| c^2=a^2+b^2-2ab*cos(c) =9+49-42cos(37) c=4.9
Do you mean the c^2=a^2 +b^2-2abcos(c)
oh wow, thank you. my computer seems to be getting these responses slow.
$$3^2+7^2-2\times 21 \cos(37^\circ) = 24.4573 $$
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now take the square root to get 4.94543
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