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Find the sum of the roots to the equation: \[2x^3-13x^2+27x-28=0\] A. -1.5 B. -0.5 C. 6.5 D. 7.5
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try expanding this to see what happens - it might give you a clue:\[(x-r1)(x-r2)(x-r3)\]where r1, r2 and r3 are the 3 roots of this equation (but leave them as r1, r2, r3).
C. \[\frac{13}{2}=6.5 \]
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