Question

find each function value, if it exists.
f(t)=√(t^2+1)

A.) f(0)= ? (Simplify your answer. Type an exact answer, using radicals as needed.)

B.) The square root is not a real number.

Answer 1

Just plug in the zero inside the function. You'll get square root of one, which is one.

Answer 2

1

Answer 3

f(-8)?

Answer 4

Same stuff. Plug in the number instead of your variable. In this case "t"

Answer 5

i dont understand

Answer 6

f(x) = x
f(1) = 1
f(x) = x + 2
f(1) = 1 + 2

Answer 7

f(x) = 5x-3
f(-2) = 5(-2) - 3

Answer 8

f(-8)=?