Question

find the absolute maximum and minimum of the function f(x)=x^8/3-16x^2/3 on interval [-1,8

Answer 1

take the derivative and check the critical points and the endpoints. don't forget the critical point of zero, where the derivative is undefined

Answer 2

derivative is
\[\frac{8 (x^2-4)}{3 \sqrt[3]{x}}\] critical points are {-2,0,2} but you can ignore -2 because is it not in your interval. find
\[f(-1),f(0),f(2),f(8)\] biggest is biggest and smallest is smallest