Question

Can someone explain this problem to me as you do it. I have many more and I need to understand how to do it. Find the fixed points of a function.
f(x)=x^2-4x+6

Answer 1

\[x ^{2}-4x+6=x\]
\[x ^{2}-5x+6=0\]
\[(x-2)(x-3)\]
=\[x ^{2}-5+6\]
x=2 x=3
Points (2,2)
(3,3)

Answer 2

I don't know if this is right but I hope so