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OpenStudy (anonymous):
log2x+log2(x+3)−log2(2x−5)=3
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jhonyy9 (jhonyy9):
log2(x(x+3))/(2x-5)=3log2(2)
OpenStudy (anonymous):
thanks, i got two answers 5 and 8
jhonyy9 (jhonyy9):
x2+3x=8(2x-5) x2+3x=16x-40 x2 -13x +40=0
OpenStudy (anonymous):
yeah that's it.thanks
jhonyy9 (jhonyy9):
(x-5)(x-8)
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