Question

log_{3}0.1+2log_{3}X= log_{3}2+log_{3}5 slove for x.

Answer 1

log_{3}0.1+2log_{3}X= log_{3}2+log_{3}5 \[\rightarrow \log_{3}0.1+\log_{3}X ^{2}= \log_{3}10 \]

Answer 2

subtract from both sides log3(0,1)

Answer 3

on the right side will get log3(10/0,1)

Answer 4

and result x2 =1 so x1,2= +/- 1

Answer 5

ok... thanks

Answer 6

yw