Question

find the fiexed points
g(x)=x^2+8x+6

Answer 1

fixed points sorry

Answer 2

solve \[g(x)=x\]

Answer 3

\[g \left( x \right)=x ^{2}+8x+6\]
\[x ^{2}+8x+6=0\]

Answer 4

Is this right so far?

Answer 5

\[x^2+8x+6=x\]

solve for x

Answer 6

so what do I do from here

Answer 7

I always get confused when I have to solve for x

Answer 8

\[\left( x+4 \right)\left( x+2 \right)=?\]

Answer 9

are you just guessing?

Answer 10

no I must be wrong

Answer 11

\[x^2+8x+6=x\]

\[x^2+7x+6=0\]

Answer 12

why did the 8 change to a 7?

Answer 13

I subtracted x from both sides

Answer 14

ok that would make sence

Answer 15

now factor

Answer 16

do I go \[\left( x+6 \right)\left( x+1 \right)\]

Answer 17

oh wait like this\[\left( x+1 \right)\left( x+6 \right)=x ^{2}+7x+6x\]

Answer 18

so what is x equal to?

Answer 19

x=1 x=6

Answer 20

no

Answer 21

oh boy

Answer 22

so shat did I do wrong

Answer 23

you factored correctly...but those are not the values of x

Answer 24

if x+1=0 then x=-1

Answer 25

how do I know that?

Answer 26

subtract 1 from both sides

Answer 27

\[\left( x+6 \right)\left( x+1 \right)=0\]

Answer 28

ok so I have a fixed point of x=-1

Answer 29

so what is the other one?

Answer 30

I will be honest I am not sure

Answer 31

will it be x+6=0 then x=-6

Answer 32

yes

Answer 33

yes yea I think I jst might be getting this

Answer 34

can you walk me through one with a square root I will post

Answer 35

I will be away from my computer for about an hour or so...I'll help you later if no one else does.

Answer 36

ok thanks so much You help me a ton