Question

Given the equation x^2+y^2-8x-6y=0
(a) Write the equation in standard form.
(b) State the center, radius, and intercepts.
(c) Submit the graph.
Please show all of your work.

Answer 1

x^2+y^2-8x-6y=0
this is the equation of circle, rearranging them,
x^2-8x+y^2-6y=0 we complete the squares
x^2-8x +y^2-6y =0
x^2-8x +(8/2)^2 +y^2-6y+(6/2)^2 =0 +(8/2)^2 +(6/2)^2
x^2-8x +16 +y^2-6y+9 =0 +16 +9
x^2-8x+16 +y^2-6y+9 =25

(x-4)^2+(y-3)^2=25 ans....equation of circle

Answer 2

from the formula of the eq of circle
(x-h)^2+(y-k)^2=r^2
(x-4)^2+(y-3)^2=5^2 we see that
h=4,k=3 and r=5 ans.........

Answer 3

centre (h,k)=(4,3) with radius r=5 ans

Answer 4

http://www.wolframalpha.com/input/?i=graph+x^2%2By^2-8x-6y%3D0+

Answer 5

good luck now sclowers

Answer 6

thank you mark!

Answer 7

yw, have fun