Question

t1 = 1; t2= 1; tn-1 = tn-1 - tn? (Recursion formula)

Answer 1

its good to put subscripts in {curlys} to set it apart

Answer 2

ohh.. okay

Answer 3

t{1} = 1

t{2} = 1

t{n-1} = .....

Answer 4

otherwise it just looks like normal mathing

Answer 5

I tried: t{n - 1} = t{n-1} - t{n}
t{2 - 1} = t3-1 - t2
t{1} = t{2} - t{2}
t{1} = 1 - 1
t{1} = 0

Answer 6

ohhh, i see.

Answer 7

and the answers are: 1, 1, 0, -1, -1, 0

Answer 8

t{n} = t{n-1} - t{n-1} is always 0, since you are subtracting the same amount from itself.

it looks like a wierd recursion

Answer 9

ohh, i see..

Answer 10

is there a larger problem that this goes to?

Answer 11

ohhhhh!!! Aww man, I wrote the question wrong all this time. It's:

t{1} = 1; t{2} = 1; t{n+2} = t{n+1}-t{n}?

Answer 12

that does look better ;)

Answer 13

ohh, sorry D:

Answer 14

t{1} = 1
t{2} = 1

t{n+2} = t{n+1}-t{n}

t{3} = t{2} - t{1} = 0
t{4} = t{3} - t{2} = -1
t{5} = t{4} - t{3} = -1
t{6} = t{5} - t{4} = 0

Answer 15

ooouu, thank you amistre64! :D