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OpenStudy (anonymous):
y=log[(10-x)/(x+2)] , find y' .
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OpenStudy (anonymous):
\[y=log[\frac{10-x}{x+2}]\] \[y=log[10-x]-log[x+2]\] \[y\prime=\frac{-1}{10-x}-\frac{1}{x+2}\]
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