Question

x^2+14x+4=0

Answer 1

\[x^2+14x+4 = 0\]\[x^2+(7+\sqrt{33})x + (7-\sqrt{33})x+4 = 0\]\[x(x+7+\sqrt{33})+(7-\sqrt{33})(x+7+\sqrt{33})=0\]\[(x+7+\sqrt{33})(x+7-\sqrt{33})=0\]\[x = -7+\sqrt{33}, -(7+\sqrt{33})\]