Question

. In Triangle ABC, Cos B = (9/12) .....find Sin B.

Answer 1

\[B = \cos^{-1}(\frac{9}{12})\]

Answer 2

whered the -1 come from?

Answer 3

means "inverse"

Answer 4

ohhh ok

Answer 5

\[\text{Sin}[\text{ArcCos}[9/12]]=\frac{\sqrt{7}}{4} \]

Answer 6

wth robtobey