Question

find the vertex line of symmetry,the max/min value of quadratic function
F9x)=-2x^2+2x+6

Answer 1

for vertex use
\[x=-\frac{b}{2a}=-\frac{2}{2\times -2}=\frac{1}{2}\]

Answer 2

so axis of symmetry is
\[y=\frac{1}{2}\]to find the second coordinate of the vertex replace x by 1/2 and see what you get.
i get
\[\frac{13}{2}\] so that is your maximum

Answer 3

so the first vertex is 2/2x-2=1/2