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given exact and approximate solutoins to three decimal places y^2-20y+100=4 would the answer then be y=11???
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no 11 does not work first of all there should probably be two answers. do you want to factor?
try \[(x-10)^2=4\] so \[x-10=2\] or \[x-10=-2\] then solve each equation separately
yes,
i think i was working it out as a reg, equation
it would be 12 right
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one would be 8
for an equation with an exponent of 2 you have to factor or use the quadratic formula. yes 12 is one answer but 8 is also an answer because if you solve \[x-10=-2\] you get \[x=8\]
you got it.
cool i got it right thank you ,
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