Question

Solve the equation!

3 tan^3θ = tan θ
http://www4a.wolframalpha.com/Calculate/MSP/MSP62319i4c5h11g6ahe55000050i4h04c1g9b0g98?MSPStoreType=image/gif&s=40&w=116&h=18

Answer 1

first solve
\[3u^3=u\]
\[3u^3-u-0\]
\[u(3u^2-1)=0\]
\[u=0, 3u^2-1=0\]
\[u=0, u=\pm\frac{1}{\sqrt{3}}\] replace u by tangent and solve for x