how do i simplyify or this equation? (3m6g15)^3
(3m^6g1^5)^\[(3m ^{6}g ^{15})^{3}\]3
\[\Large (3)^3 \times m^{6\times 3} \times g^{15 \times 3}\]
\[\Large 27m^{18}g^{45}\]
can you help me with another one? i do not get the hang of this
umm, okay. lol.
\[5x ^{2}\sqrt{3x ^{12}} \times 9\sqrt{3x ^{20}}\]
?
u here?
yea
i sent the equation
solving..
i am totally confused on simplying these radicals like this
Do u want the simplified answer? if u are doing online thing
\[\sqrt{16}x ^{6} \over \sqrt{448}\] this stumbles me. the equation i sent well i tried it and i got it wrong on my webstie called studyisland
\[\Large 135x^{18}\] this is for the one about this..
\[\sqrt{16x ^{6}} \over \sqrt{448}\]is that like this?
the 135x^18 is the answer for the other one but what is the answer and how do you get it for the one you sent \[\sqrt{16x ^{2}} \over \sqrt{448}\]
i dont know how to solve problems like this, can you help me with the processes so i can do it by myself?
\[5x ^{2}\sqrt{3x ^{12}} \times 9\sqrt{3x ^{20}}\] \[(5*9)x^2 \sqrt{9x^{32}}\] \[45x^2*3 \sqrt{ x^{32}}\] \[135x^{2+16}\] \[135x^{18}\]
how about \[\sqrt{16x ^{2}}\over \sqrt{448}\]
i wil be back in 5mins.. can u wait please?
i can wait
i mean, this is proper problem \[\sqrt{16x ^{6}}\over \sqrt{448}\]
?
\[\sqrt{\frac{16x^6}{448}}\] \[\sqrt{\frac{1x^6}{28}}\] \[\frac{x^3}{2\sqrt7}\]answer
how did you get that?
i showed u the working..
how did you get 1x6^
i mean 1x^6
|dw:1321840080450:dw|
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