Question

A ball is dropped from a tower and reaches the ground in 4 seconds. Find:

a) the height of the tower
b)the velocity of the ball when is hits the ground

Answer 1

V=Vo+at
V^2=Vo^2+2a(X-Xo)
S=So+Vot+1/2(a*t^2)

Yu use this formulas to solve it. Do you know where to go from here?

Answer 2

but there is no v and a?

Answer 3

As the ball is dropped down the building yur acceleration = gravity (9.81m/s^2 or 32.2ft/s^2) and we also know that the initial velocity is 0 (zero) because the ball was dropped, not thrown.

Answer 4

oh thank you for the help:)

Answer 5

np (;