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OpenStudy (anonymous):
jhonyy9 (jhonyy9):
???
OpenStudy (anonymous):
9^2x+1=(1/27)^7x-5
jhonyy9 (jhonyy9):
us 9=3 squared and 1/27 = 3 on exponent -3
jhonyy9 (jhonyy9):
after thhis us ligarithm
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jhonyy9 (jhonyy9):
sorry logarithm
jhonyy9 (jhonyy9):
like log base 3
OpenStudy (anonymous):
Im not really sure how i would apply that on this problem
jhonyy9 (jhonyy9):
so there will be 2log3(3) this will be 9
jhonyy9 (jhonyy9):
and -3log3(3) this will be 1/27
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jhonyy9 (jhonyy9):
and now after this you will get that 2(2x+1)= -3(7x-5) these will be exponents og log3(3) on both sides
jhonyy9 (jhonyy9):
ok ?
jhonyy9 (jhonyy9):
now you need just equalis those exponets and calcule for what value of x this is equal
jhonyy9 (jhonyy9):
ok ?
OpenStudy (anonymous):
do i need to distribute the 2 and the -3?
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OpenStudy (anonymous):
then solve for x?
jhonyy9 (jhonyy9):
yes this equation - equality - what you have got from exponents
jhonyy9 (jhonyy9):
comen now is easy
jhonyy9 (jhonyy9):
4x+2= -21x+15
jhonyy9 (jhonyy9):
right ?
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OpenStudy (anonymous):
x=13/25?
jhonyy9 (jhonyy9):
yes was difficile ?
OpenStudy (anonymous):
not after i had the 2(2x+1) but i dont know the log stuff or exactly how you got there
jhonyy9 (jhonyy9):
check it in your math book when there are exercise like this we need using logarithm to getting the finaly equation after what we can solve it we will get the neecessary solutions