write the following quadratics in the form
y=(x-h)^2 +k using completing the squares and hence sketch each function and stating the vertex
a) y= x^2 -6x+5
b) y= x^2 +8x -2
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OpenStudy (ash2326):
a)
y=x^2-6x+5
y=x^2-6x+9-4
y=(x-3)^2+(-4)
vertex (3,-4)
b)
y=x^2+8x+5
y=x^2+8x+16-21
y=(x+4)^2-21
y=(x-(-4))^2-21
vertex (-4,-21)
jhonyy9 (jhonyy9):
b. not is correct
jhonyy9 (jhonyy9):
why -21 ?
jhonyy9 (jhonyy9):
just -11
jhonyy9 (jhonyy9):
right ???
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jhonyy9 (jhonyy9):
but in point b. there is +2 and not +5 like last term
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OpenStudy (anonymous):
hmmm i think its supposed to be 18?
OpenStudy (anonymous):
woopppss the question b) was supposed to be x^2+8x-2
jhonyy9 (jhonyy9):
you need checking how can you get 8 can us 6+2 or 4+4 or 5+3 or 7+1 or ????
OpenStudy (anonymous):
instead of +5 haha
OpenStudy (ash2326):
sorry kirsten i solved for +5
y=(x-(-4))^2-18
vertex (-4,-18)
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jhonyy9 (jhonyy9):
yes and after you check how can you getting the needed number what will result from product of used numbers for 8 and after you will get how many you need subtracting from that