write the following quadratics in the form y=(x-h)^2 +k using completing the squares and hence sketch each function and stating the vertex a) y= x^2 -6x+5 b) y= x^2 +8x -2
a) y=x^2-6x+5 y=x^2-6x+9-4 y=(x-3)^2+(-4) vertex (3,-4) b) y=x^2+8x+5 y=x^2+8x+16-21 y=(x+4)^2-21 y=(x-(-4))^2-21 vertex (-4,-21)
b. not is correct
why -21 ?
just -11
right ???
but in point b. there is +2 and not +5 like last term
sorry -11
oh not +5 there is -2
y=x^2+8x+5 y=x^2+8x+16-11 y=(x+4)^2-11 y=(x-(-4))^2-11 vertex (-4,-11)
hmmm i think its supposed to be 18?
woopppss the question b) was supposed to be x^2+8x-2
you need checking how can you get 8 can us 6+2 or 4+4 or 5+3 or 7+1 or ????
instead of +5 haha
sorry kirsten i solved for +5 y=(x-(-4))^2-18 vertex (-4,-18)
yes and after you check how can you getting the needed number what will result from product of used numbers for 8 and after you will get how many you need subtracting from that
ok ?
yapppp :) awesome thank you guys
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