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Mathematics 19 Online
OpenStudy (anonymous):

helpp ?? √x+2+4=x

OpenStudy (anonymous):

x+2 is under the squareroot?

jhonyy9 (jhonyy9):

sqrt(x+2)=x-4 squared both sides x+2=x2 -8x+16 x2 -9x +14 =0 (x-7)(x-2)=0 x1 = 7 x2 = 2

jhonyy9 (jhonyy9):

ok ?

jhonyy9 (jhonyy9):

right ?

OpenStudy (anonymous):

yeah x+2 is under the square rooot

OpenStudy (anonymous):

Then jhonny got it right =)

OpenStudy (nikvist):

\[x=2\quad\mbox{isn't solution of this equation,only }\quad x=7\]

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