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Mathematics 21 Online
OpenStudy (anonymous):

verify the identity: cos x+sin x tan x=sec x

OpenStudy (anonymous):

nvm got it!

OpenStudy (slaaibak):

LHS: cos x + sin^2 x/cos x = (cos^2 x + sin^2 x)/cos x = 1/cosx =sec x

OpenStudy (anonymous):

sinx tanx = secx -cos x =(1/cosx)-cosx =(1 - cos^2x)/cosx = (sin^2x)/cosx = sinx sinx/cosx = sinx tanx

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