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Relative error questions Using her ruler, Partha measured the sides of a rectangle to be 13 cm by 7 cm. The actual measurements are 13.5 cm by 6.5cm. Find parthas Relative error in calculating the area of the rectangle to the nearest thousandth and the percent of error to the nearest tenth. SHOW ALL WORK! If you can, please explain how you got Ur answer
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for relative error the equation is: \[ABS(actual-measured)/actual\]
so in your case it would be...
And then since you're calculating the error in area you would use your calculated relative errors and actual values for L and W and plug them into this equation to get relative error for area: \[\Delta A=\Delta W*L+W*\Delta L\] \[\Delta A=rel. error for Area\]
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