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f(x)=cos(tan2x). Find f'(x)
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\[f'(x)=-2\sin(\tan2x)\sec^22x\]
thanks :)
In case you want to use a non-human: http://www.wolframalpha.com/ Enter your function in the slot here and type the word derivative before it. Free mindless calculations!
thanks that would help a lot haha
Here's your particular problem: http://www.wolframalpha.com/input/?i=derivative+cos%28tan2x%29
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turing will be u be online for a while?
Um, sort of, but I will be having dinner so I may be distracted an bit.
means u can help! YAY! =D
Where? How?
i will post some questions..
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Cool I hope I can help Nice straightforward calculus please! :D
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